## C# || How To Find Product Of Array Except Self Using C#

The following is a module with functions which demonstrates how to find the product of an array except itself using C#.

1. Product Except Self – Problem Statement

Given an integer array **nums**, return *an array* **answer** *such that* **answer[i]** *is equal to the product of all the elements of* **nums** *except* **nums[i]**.

The product of any prefix or suffix of **nums** is **guaranteed** to fit in a **32-bit** integer.

You must write an algorithm that runs in **O(n)** time and without using the division operation.

**Example 1:**

Input: nums = [1,2,3,4]

Output: [24,12,8,6]

**Example 2:**

Input: nums = [-1,1,0,-3,3]

Output: [0,0,9,0,0]

2. Product Except Self – Solution

The following is a solution which demonstrates how to find the product of an array except itself.

In this solution, the product for **result[i]** is calculated by scanning the input array, and multiplying the numbers that come before the current **i**, and the numbers that come after the current **i**.

First, the running product of the numbers that come before the current **i** is calculated by scanning the array starting from the beginning (prefix).

Then, the running product of the numbers that come after the current **i** is calculated by scanning the array starting from the end (suffix).

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// ============================================================================// Author: Kenneth Perkins// Date: Nov 26, 2021// Taken From: http://programmingnotes.org/// File: Solution.cs// Description: Demonstrates how to find product of array except self// ============================================================================public class Solution { public int[] ProductExceptSelf(int[] nums) { var result = new int[nums.Length]; // Prefix var runningPrefix = 1; for (int index = 0; index < nums.Length; ++index) { result[index] = runningPrefix; runningPrefix *= nums[index]; } // Suffix var runningSufix = 1; for (int index = nums.Length - 1; index >= 0; --index) { result[index] *= runningSufix; runningSufix *= nums[index]; } return result; }}// http://programmingnotes.org/

**QUICK NOTES**:

The highlighted lines are sections of interest to look out for.

The code is heavily commented, so no further insight is necessary. If you have any questions, feel free to leave a comment below.

Once compiled, you should get this as your output for the example cases:

[24,12,8,6]

[0,0,9,0,0]

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