## Monthly Archives: June 2022

## C# || How To Find The Shortest Clear Path In A Binary Matrix Using C#

The following is a module with functions which demonstrates how to find the shortest clear path in a binary matrix using C#.

1. Shortest Path Binary Matrix – Problem Statement

Given an **n x n** binary matrix **grid**, return *the length of the shortest clear path in the matrix*. If there is no clear path, return

**-1**.

A **clear path** in a binary matrix is a path from the **top-left** cell (i.e., **(0, 0)**) to the **bottom-right** cell (i.e., **(n – 1, n – 1)**) such that:

- All the visited cells of the path are
**0**. - All the adjacent cells of the path are
**8-directionally**connected (i.e., they are different and they share an edge or a corner).

The **length of a clear path** is the number of visited cells of this path.

**Example 1:**

Input:grid = [[0,1],[1,0]]

Output:2

**Example 2:**

Input:grid = [[0,0,0],[1,1,0],[1,1,0]]

Output:4

**Example 3:**

Input:grid = [[1,0,0],[1,1,0],[1,1,0]]

Output:-1

2. Shortest Path Binary Matrix – Solution

The following is a solution which demonstrates how find the shortest clear path in a binary matrix.

```
```
123456789101112131415161718192021222324252627282930313233343536373839404142434445464748495051525354555657585960616263646566
// ============================================================================// Author: Kenneth Perkins// Date: Jun 3, 2022// Taken From: http://programmingnotes.org/// File: Solution.cs// Description: Demonstrates how to find shortest path binary matrix// ============================================================================public class Solution { // Search directions List<KeyValuePair<int, int>> directions = new List<KeyValuePair<int, int>>() { // Direction coordinates: (y, x) new KeyValuePair<int, int>(0, -1), new KeyValuePair<int, int>(0, 1), new KeyValuePair<int, int>(-1, 0), new KeyValuePair<int, int>(1, 0), new KeyValuePair<int, int>(1, 1), new KeyValuePair<int, int>(-1, -1), new KeyValuePair<int, int>(-1, 1), new KeyValuePair<int, int>(1, -1) }; public int ShortestPathBinaryMatrix(int[][] grid) { var NOT_VISITED = 0; var VISITED = 1; if (grid[0][0] == VISITED) { return -1; } var queue = new Queue<KeyValuePair<int, int>>(); queue.Enqueue(new KeyValuePair<int, int>(0, 0)); grid[0][0] = VISITED; var result = 0; while(queue.Count > 0) { ++result; for (var itemCount = queue.Count; itemCount > 0; --itemCount) { var current = queue.Dequeue(); // Get the current coordinates var row = current.Key; var col = current.Value; if (row == grid.Length - 1 && col == grid[row].Length - 1) { return result; } // Search in different directions foreach (var direction in directions) { var newRow = row + direction.Key; var newCol = col + direction.Value; if (IsValidCell(grid, newRow, newCol) && grid[newRow][newCol] == NOT_VISITED) { grid[newRow][newCol] = VISITED; queue.Enqueue(new KeyValuePair<int, int>(newRow, newCol)); } } } } return -1; } private bool IsValidCell(int[][] grid, int row, int col) { return row >= 0 && row < grid.Length && col >= 0 && col < grid[row].Length; }}// http://programmingnotes.org/

**QUICK NOTES**:

The highlighted lines are sections of interest to look out for.

The code is heavily commented, so no further insight is necessary. If you have any questions, feel free to leave a comment below.

Once compiled, you should get this as your output for the example cases:

2

4

-1

## C# || Palindromic Substrings – How To Find The Number Of Palindromic Substrings Using C#

The following is a module with functions which demonstrates how to find the number of palindromic substrings using C#.

1. Count Substrings – Problem Statement

Given a string **s**, return *the number of palindromic substrings in it*.

A string is a **palindrome** when it reads the same backward as forward.

A **substring** is a contiguous sequence of characters within the string.

**Example 1:**

Input:s = "abc"

Output:3

Explanation:Three palindromic strings: "a", "b", "c".

**Example 2:**

Input:s = "aaa"

Output:6

Explanation:Six palindromic strings: "a", "a", "a", "aa", "aa", "aaa".

2. Count Substrings – Solution

The following is a solution which demonstrates how to find the number of palindromic substrings.

```
```
12345678910111213141516171819202122232425
// ============================================================================// Author: Kenneth Perkins// Date: Jun 2, 2022// Taken From: http://programmingnotes.org/// File: Solution.cs// Description: Demonstrates how to find palindromic substrings// ============================================================================public class Solution { public int CountSubstrings(string s) { var count = 0; for (var index = 0; index < s.Length; ++index) { count += CountPalindrome(s, index, index); // Count even sized count += CountPalindrome(s, index, index + 1); // Count odd sized } return count; } private int CountPalindrome(string s, int start, int end) { var count = 0; while (start >= 0 && end < s.Length && s[start--] == s[end++]) { ++count; } return count; }}// http://programmingnotes.org/

**QUICK NOTES**:

The highlighted lines are sections of interest to look out for.

The code is heavily commented, so no further insight is necessary. If you have any questions, feel free to leave a comment below.

Once compiled, you should get this as your output for the example cases:

3

6