## C# || How To Generate Next Permutation From Array Using C#

The following is a module with functions which demonstrates how to generate the next permutation from an array using C#.

1. Next Permutation – Problem Statement

Implement **next permutation**, which rearranges numbers into the lexicographically next greater permutation of numbers.

If such an arrangement is not possible, it must rearrange it as the lowest possible order (i.e., sorted in ascending order).

The replacement must be **in place** and use only constant extra memory.

**Example 1:**

Input: nums = [1,2,3]

Output: [1,3,2]

**Example 2:**

Input: nums = [3,2,1]

Output: [1,2,3]

**Example 3:**

Input: nums = [1,1,5]

Output: [1,5,1]

**Example 4:**

Input: nums = [1]

Output: [1]

2. Next Permutation – Solution

The following is a solution which demonstrates how to generate the next permutation from an array

```
```
12345678910111213141516171819202122232425262728293031323334353637383940414243444546474849505152
// ============================================================================// Author: Kenneth Perkins// Date: Oct 27, 2021// Taken From: http://programmingnotes.org/// File: Solution.cs// Description: Demonstrates how to generate the next permutation// ============================================================================public class Solution { public void NextPermutation(int[] nums) { // Starting from the end, look for the first index that is not in descending order var startIndex = nums.Length - 2; while (startIndex >= 0) { // Find first decreasing element if (nums[startIndex] < nums[startIndex + 1]) { break; } --startIndex; } if (startIndex >= 0) { // Starting from the end, look for the first element greater than the start index int endIndex = nums.Length - 1; while (endIndex > startIndex) { // Find first greater element if (nums[endIndex] > nums[startIndex]) { break; } --endIndex; } // Swap first and last elements Swap(ref nums[startIndex], ref nums[endIndex]); } // Reverse the array Reverse(nums, startIndex + 1); } private void Reverse(int[] nums, int startIndex) { for (int start = startIndex, end = nums.Length - 1; start < end; ++start, --end) { Swap(ref nums[start], ref nums[end]); } } private void Swap(ref int a, ref int b) { var tmp = a; a = b; b = tmp; }}// http://programmingnotes.org/

**QUICK NOTES**:

The highlighted lines are sections of interest to look out for.

The code is heavily commented, so no further insight is necessary. If you have any questions, feel free to leave a comment below.

Once compiled, you should get this as your output for the example cases:

[1,3,2]

[1,2,3]

[1,5,1]

[1]

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