## C# || How To Determine The Maximum Units On A Truck Using C# The following is a module with functions which demonstrates how to determine the maximum units on a truck using C#.

1. Maximum Units – Problem Statement

You are assigned to put some amount of boxes onto one truck. You are given a 2D array boxTypes, where boxTypes[i] = [numberOfBoxes, numberOfUnitsPerBox]:

``` • numberOfBoxes is the number of boxes of type i. • numberOfUnitsPerBox is the number of units in each box of the type i ```

You are also given an integer truckSize, which is the maximum number of boxes that can be put on the truck. You can choose any boxes to put on the truck as long as the number of boxes does not exceed truckSize.

Return the maximum total number of units that can be put on the truck.

Example 1:

``` Input: boxTypes = [[1,3],[2,2],[3,1]], truckSize = 4 Output: 8 Explanation: There are: - 1 box of the first type that contains 3 units. - 2 boxes of the second type that contain 2 units each. - 3 boxes of the third type that contain 1 unit each. You can take all the boxes of the first and second types, and one box of the third type. The total number of units will be = (1 * 3) + (2 * 2) + (1 * 1) = 8. ```

Example 2:

``` Input: boxTypes = [[5,10],[2,5],[4,7],[3,9]], truckSize = 10 Output: 91 ```

2. Maximum Units – Solution

The following is a solution which demonstrates how to determine the maximum units on a truck.

In this solution, we start with the box with the most units. The box types are sorted by the number of units per box in descending order. Then, the box types are iterated over, taking from each type as many as possible.

``` 2. Maximum Units - Solution C# // ============================================================================ // Author: Kenneth Perkins // Date: Oct 13, 2021 // Taken From: http://programmingnotes.org/ // File: Solution.cs // Description: Determines the maximum units you can put on a truck // ============================================================================ public class Solution { public int MaximumUnits(int[][] boxTypes, int truckSize) { var result = 0; // Sort the box types by number of units per box in descending order Array.Sort(boxTypes, (a, b) => { return b - a; }); // Determine how many units can be added to the truck var remainingSize = truckSize; foreach (var type in boxTypes) { // Get the box count and units per box var boxCount = type; var unitsPerBox = type; // Check to see if theres enough room to add more boxes var adjustedBoxCount = 0; if (remainingSize - boxCount > 0) { adjustedBoxCount = boxCount; // All boxes can be added } else { adjustedBoxCount = remainingSize; // Only the remaining amount can be added } // Add the units to the result result += adjustedBoxCount * unitsPerBox; // Adjust remaining truck size with the added boxes remainingSize -= adjustedBoxCount; // Exit if there is no more room remaining if (remainingSize == 0) { break; } } return result; } }// http://programmingnotes.org/ 12345678910111213141516171819202122232425262728293031323334353637383940414243444546 // ============================================================================//    Author: Kenneth Perkins//    Date:   Oct 13, 2021//    Taken From: http://programmingnotes.org///    File:  Solution.cs//    Description: Determines the maximum units you can put on a truck// ============================================================================public class Solution {    public int MaximumUnits(int[][] boxTypes, int truckSize) {        var result = 0;         // Sort the box types by number of units per box in descending order        Array.Sort(boxTypes, (a, b) => {           return b - a;        });         // Determine how many units can be added to the truck        var remainingSize = truckSize;        foreach (var type in boxTypes) {            // Get the box count and units per box            var boxCount = type;            var unitsPerBox = type;             // Check to see if theres enough room to add more boxes            var adjustedBoxCount = 0;            if (remainingSize - boxCount > 0) {                adjustedBoxCount = boxCount; // All boxes can be added            } else {                adjustedBoxCount = remainingSize; // Only the remaining amount can be added            }             // Add the units to the result            result += adjustedBoxCount * unitsPerBox;             // Adjust remaining truck size with the added boxes            remainingSize -= adjustedBoxCount;             // Exit if there is no more room remaining            if (remainingSize == 0) {                break;            }        }         return result;    }}// http://programmingnotes.org/ ```

QUICK NOTES:
The highlighted lines are sections of interest to look out for.

The code is heavily commented, so no further insight is necessary. If you have any questions, feel free to leave a comment below.

Once compiled, you should get this as your output for the example cases:

``` 8 91 ```