## Tag Archives: two-pointer

## C# || How To Sort An Array By Parity Using C#

The following is a module with functions which demonstrates how to sort an array by parity using C#.

1. Sort Array By Parity – Problem Statement

Given an integer array **nums**, move all the even integers at the beginning of the array followed by all the odd integers.

Return * any array that satisfies this condition*.

**Example 1:**

Input:nums = [3,1,2,4]

Output:[2,4,3,1]

Explanation:The outputs [4,2,3,1], [2,4,1,3], and [4,2,1,3] would also be accepted.

**Example 2:**

Input:nums = [0]

Output:[0]

2. Sort Array By Parity – Solution

The following is a solution which demonstrates how to sort an array by parity.

```
```
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// ============================================================================// Author: Kenneth Perkins// Date: Dec 1, 2023// Taken From: http://programmingnotes.org/// File: Solution.cs// Description: Demonstrates how to sort an array by parity// ============================================================================public class Solution { public int[] SortArrayByParity(int[] nums) { var startIndex = 0; var endIndex = nums.Length -1; while (startIndex < endIndex) { if (IsOdd(nums[startIndex])) { var temp = nums[startIndex]; nums[startIndex] = nums[endIndex]; nums[endIndex] = temp; --endIndex; } else { ++startIndex; } } return nums; } private bool IsOdd(int num) { return num % 2 != 0; }}// http://programmingnotes.org/

**QUICK NOTES**:

The highlighted lines are sections of interest to look out for.

The code is heavily commented, so no further insight is necessary. If you have any questions, feel free to leave a comment below.

Once compiled, you should get this as your output for the example cases:

[4,2,1,3]

[0]

## C# || How To Find Interval List Intersections From Two Arrays Using C#

The following is a module with functions which demonstrates how to find interval list intersections from two arrays using C#.

1. Interval Intersection – Problem Statement

You are given two lists of closed intervals, **firstList** and **secondList**, where **firstList[i] = [start _{i}, end_{i}]** and

**secondList[j] = [start**. Each list of intervals is pairwise

_{j}, end_{j}]**disjoint**and in

**sorted order**.

Return *the intersection of these two interval lists*.

A **closed interval** **[a, b]** (with **a <= b**) denotes the set of real numbers **x** with **a <= x <= b**.

The **intersection** of two closed intervals is a set of real numbers that are either empty or represented as a closed interval. For example, the intersection of **[1, 3]** and **[2, 4]** is **[2, 3]**.

**Example 1:**

Input: firstList = [[0,2],[5,10],[13,23],[24,25]], secondList = [[1,5],[8,12],[15,24],[25,26]]

Output: [[1,2],[5,5],[8,10],[15,23],[24,24],[25,25]]

**Example 2:**

Input: firstList = [[1,3],[5,9]], secondList = []

Output: []

**Example 3:**

Input: firstList = [], secondList = [[4,8],[10,12]]

Output: []

**Example 4:**

Input: firstList = [[1,7]], secondList = [[3,10]]

Output: [[3,7]]

2. Interval Intersection – Solution

The following is a solution which demonstrates how to find interval list intersections from two arrays.

This solution uses the two pointer technique when looking for valid interval intersections.

```
```
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// ============================================================================// Author: Kenneth Perkins// Date: Nov 23, 2021// Taken From: http://programmingnotes.org/// File: Solution.cs// Description: Demonstrates how to find interval list intersections// ============================================================================public class Solution { public int[][] IntervalIntersection(int[][] firstList, int[][] secondList) { var result = new List<int[]>(); // Go through first and second array looking for range intersection var indexFirst = 0; var indexSecond = 0; while (indexFirst < firstList.Length && indexSecond < secondList.Length) { // Get the first and second array var first = firstList[indexFirst]; var second = secondList[indexSecond]; // Check to see if this is a valid intersection if (first[1] >= second[0] && first[0] <= second[1]) { // Get starting and ending range from the two arrays var start = Math.Max(first[0], second[0]); var end = Math.Min(first[1], second[1]); result.Add(new int[] {start, end}); } // Increment array index depending on which range is completely satisfied if (first[1] < second[1]) { ++indexFirst; } else { ++indexSecond; } } return result.ToArray(); }}// http://programmingnotes.org/

**QUICK NOTES**:

The highlighted lines are sections of interest to look out for.

The code is heavily commented, so no further insight is necessary. If you have any questions, feel free to leave a comment below.

Once compiled, you should get this as your output for the example cases:

[[1,2],[5,5],[8,10],[15,23],[24,24],[25,25]]

[]

[]

[[3,7]]