Daily Archives: February 5, 2021

C++ || How To Get The Day Of The Week & The Week Day Name From A Date Using C++

The following is a module with functions which demonstrates how to get the day of the week and the week day name from a given date using C++.

The function demonstrated on this page uses Zeller’s congruence to determine the day of the week from a given date.


1. Week Day

The example below demonstrates the use of ‘Utils::getWeekday‘ to get the day of week for a given date. The following function returns a value from a DayOfWeek enum, which represents the day of the week for the given parameters.

The following are possible values that are returned from this function:


• 0 = Sunday
• 1 = Monday
• 2 = Tuesday
• 3 = Wednesday
• 4 = Thursday
• 5 = Friday
• 6 = Saturday


2. Week Day Name

The example below demonstrates the use of ‘Utils::getWeekdayName‘ to get the name of the day of week for the given date.

The following are possible values that are returned from this function:


• Sunday
• Monday
• Tuesday
• Wednesday
• Thursday
• Friday
• Saturday


3. Utils Namespace

The following is the Utils Namespace. Include this in your project to start using!


4. More Examples

Below are more examples demonstrating the use of the ‘Utils‘ Namespace. Don’t forget to include the module when running the examples!

QUICK NOTES:
The highlighted lines are sections of interest to look out for.

The code is heavily commented, so no further insight is necessary. If you have any questions, feel free to leave a comment below.

C++ || Simple Multi Digit, Decimal & Negative Number Infix To Postfix Conversion & Evaluation

The following is sample code which demonstrates the implementation of a multi digit, decimal, and negative number infix to postfix converter and evaluator using C++.

The program demonstrated on this page has the ability to convert and evaluate a single digit, multi digit, decimal number, and/or negative number infix equation. So for example, if the the infix equation of (19.87 * -2) was entered into the program, the converted postfix expression of 19.87 -2 * would display to the screen, as well as the final evaluated answer of -39.74.

REQUIRED KNOWLEDGE FOR THIS PROGRAM

How To Convert Infix To Postfix
How To Evaluate A Postfix Expression


1. Overview

The program demonstrated on this page is different from a previous implementation of the same type in that this version does not use a Finite State Machine during the conversion process, which simplifies the implemetation!

This program has the following flow of control:

• Get an infix expression from the user
• Convert the infix expression to postfix & isolate all of the math operators, multi digit, decimal, negative and single digit numbers that are found in the postfix expression
• Evaluate the postfix expression by breaking the infix string into tokens found from the above step
• Display the evaluated answer to the screen

The above steps are implemented below.


2. Infix To Posfix Conversion & Evaluation


QUICK NOTES:
The highlighted lines are sections of interest to look out for.

The code is heavily commented, so no further insight is necessary. If you have any questions, feel free to leave a comment below.

The following is sample output.

====== RUN 1 ======

==== Infix To Postfix Conversion & Evaluation ====

Math Operators:
+ || Addition
- || Subtraction
* || Multiplication
/ || Division
% || Modulus
^ || Power
$ || Square Root
s || Sine
c || Cosine
t || Tangent
- || Negative Number
Sample Infix Equation: ((s(-4^5)*1.4)/($(23+2)--2.8))*(c(1%2)/(7.28*.1987)^(t23))

Please enter an Infix expression: 12/3*9

The Infix expression = 12/3*9
The Postfix expression = 12 3 / 9 *

Calculations:
12/3 = 4
4*9 = 36

Final answer = 36

====== RUN 2 ======

==== Infix To Postfix Conversion & Evaluation ====

Math Operators:
+ || Addition
- || Subtraction
* || Multiplication
/ || Division
% || Modulus
^ || Power
$ || Square Root
s || Sine
c || Cosine
t || Tangent
- || Negative Number
Sample Infix Equation: ((s(-4^5)*1.4)/($(23+2)--2.8))*(c(1%2)/(7.28*.1987)^(t23))

Please enter an Infix expression: -150.89996 - 87.56643

The Infix expression = -150.89996 - 87.56643
The Postfix expression = -150.89996 87.56643 -

Calculations:
-150.9-87.5664 = -238.466

Final answer = -238.466

====== RUN 3 ======

==== Infix To Postfix Conversion & Evaluation ====

Math Operators:
+ || Addition
- || Subtraction
* || Multiplication
/ || Division
% || Modulus
^ || Power
$ || Square Root
s || Sine
c || Cosine
t || Tangent
- || Negative Number
Sample Infix Equation: ((s(-4^5)*1.4)/($(23+2)--2.8))*(c(1%2)/(7.28*.1987)^(t23))

Please enter an Infix expression: ((s(-4^5)*1.4)/($(23+2)--2.8))*(c(1%2)/(7.28*.1987)^(t23))

The Infix expression = ((s(-4^5)*1.4)/($(23+2)--2.8))*(c(1%2)/(7.28*.1987)^(t23))
The Postfix expression = -4 5 ^ s 1.4 * 23 2 + $ -2.8 - / 1 2 % c 7.28 .1987 * 23 t ^ / *

Calculations:
-4^5 = -1024
sin(-1024) = 0.158533
0.158533*1.4 = 0.221947
23+2 = 25
√25 = 5
5--2.8 = 7.8
0.221947/7.8 = 0.0284547
1%2 = 1
cos(1) = 0.540302
7.28*0.1987 = 1.44654
tan(23) = 1.58815
1.44654^1.58815 = 1.79733
0.540302/1.79733 = 0.300614
0.0284547*0.300614 = 0.00855389

Final answer = 0.00855389

====== RUN 4 ======

==== Infix To Postfix Conversion & Evaluation ====

Math Operators:
+ || Addition
- || Subtraction
* || Multiplication
/ || Division
% || Modulus
^ || Power
$ || Square Root
s || Sine
c || Cosine
t || Tangent
- || Negative Number
Sample Infix Equation: ((s(-4^5)*1.4)/($(23+2)--2.8))*(c(1%2)/(7.28*.1987)^(t23))

Please enter an Infix expression: (1987 + 1991) * -1

The Infix expression = (1987 + 1991) * -1
The Postfix expression = 1987 1991 + -1 *

Calculations:
1987+1991 = 3978
3978*-1 = -3978

Final answer = -3978

====== RUN 5 ======

==== Infix To Postfix Conversion & Evaluation ====

Math Operators:
+ || Addition
- || Subtraction
* || Multiplication
/ || Division
% || Modulus
^ || Power
$ || Square Root
s || Sine
c || Cosine
t || Tangent
- || Negative Number
Sample Infix Equation: ((s(-4^5)*1.4)/($(23+2)--2.8))*(c(1%2)/(7.28*.1987)^(t23))

Please enter an Infix expression: (1+(2*((3+(4*5))*6)))

The Infix expression = (1+(2*((3+(4*5))*6)))
The Postfix expression = 1 2 3 4 5 * + 6 * * +

Calculations:
4*5 = 20
3+20 = 23
23*6 = 138
2*138 = 276
1+276 = 277

Final answer = 277